2x^2+400=1650

Solution for 2x^2+400=1650 equation:

2x^2+400=1650

We move all terms to the left:

2x^2+400-(1650)=0

We add all the numbers together, and all the variables

2x^2-1250=0

a = 2; b = 0; c = -1250;
Δ = b2-4ac
Δ = 02-4·2·(-1250)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*2}=\frac{-100}{4}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*2}=\frac{100}{4}
=25
$